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GR9677 #41
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Alternate Solutions |
greatm31
2008-11-07 16:52:09 | I think the problem is slightly confusing because in the question, it refers to the state of the hydrogen ATOM, and in the answers it is referring to the configuration of just the ELECTRON. The whole atom can be either in the spin singlet (s=0) or spin triplet (s=1) states. From the superscript 3=2s+1, s=1, so the state is spin triplet. But you don't need that for the answer:
If we want to write the original state of JUST THE ELECTRON, we use the given info that it's a "3p electron" so for just the electron, l=1. And the spin of JUST THE ELECTRON is s=1/2 (the spin an electron is ALWAYS 1/2). So the original configuration of the ELECTRON is:
Where j=l+s for the electron. Now you can apply your selection rules and see that (A) is the only option since  , getting you l=0 and j=l+s=1/2. |  |
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Comments |
GREview
2009-09-16 14:38:54 | This QUESTION has a TYPO in:
"A 3p electron is found in the  energy level of a hydrogen atom."
Spectroscopic notation consists of:  . All "energy levels" of atoms house electrons, so the multiplicity ( ) of an energy level is ALWAYS going to be  because an electron ALWAYS has  .
The same typo is repeated in choice E, where the multiplicity is again 3. |  | greatm31
2008-11-07 16:52:09 | I think the problem is slightly confusing because in the question, it refers to the state of the hydrogen ATOM, and in the answers it is referring to the configuration of just the ELECTRON. The whole atom can be either in the spin singlet (s=0) or spin triplet (s=1) states. From the superscript 3=2s+1, s=1, so the state is spin triplet. But you don't need that for the answer:
If we want to write the original state of JUST THE ELECTRON, we use the given info that it's a "3p electron" so for just the electron, l=1. And the spin of JUST THE ELECTRON is s=1/2 (the spin an electron is ALWAYS 1/2). So the original configuration of the ELECTRON is:
Where j=l+s for the electron. Now you can apply your selection rules and see that (A) is the only option since , getting you l=0 and j=l+s=1/2. | | phys2718
2008-10-09 10:02:12 | After spending a long time checking sources on Quantum Mechanics I've decided that the superscript "3" for the spectroscopic notation in the statement of the problem is a typo or a mistake. The single electron in Hydrogen has spin s = 1/2, so this number has to be a 2, period.
DDO
2008-10-29 16:49:12 |
Moreover this implies that the spin of the electron changes during the transition (since answer A has a different total spin than the initial state and there is only 1 electron), this is not allowed for an electric dipole transition. 
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|  | georgi
2007-08-30 21:55:33 | delta m should also be -1. recall that the total angular momentum orbital number changed from 3/2 to 1/2. Also, the total orbital number l changed from 1 to 0 since m = -l, -l+1, ...l m =0 as well. thus it switched from m=1 to m=0 making a transition of delta m = -1 | | physicsanator
2007-04-12 14:20:16 | The spectroscopic notation is for the top left number, the multiplicity, equal to 2s+1, for the bottom right number, the total angular momentum, J. The letter in the middle, is simply your orbital angular momentum, corresponding to your orbitals, s (l=0) p(l=1) d(l=2) and so forth.
m, the magnetic quantum number, ranges in values from -l to +l, so for each letter in the middle you have different m values. | | hamood
2007-04-09 18:48:12 | I am confused about this, I thought the notation was rn^2s+1 L _jrnwont that mean that 2s+1 =3, meaning s =1 for this case..but shouldnt an electron have an s of 1/2...also how do we get the delta m value from the notation?
georgi
2007-08-30 21:58:18 |
the S in 2s+1 is the sum of all the  of which the electron has =1/2. The total spin quantum number is not necessarily 1/2 for an electron and depends on the system. delta m is obtained from the fact that we know j = +  . In our case delta m is talking about the value, which changes from 1 to 0. hope this helps.
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|  | cyberdeathreaper
2007-01-15 19:48:07 | Those wondering how to decipher the notation in the question should check out the article on wikipedia for "term symbol"
FortranMan
2008-08-16 12:44:01 |
Hund's Rules is a better place to start. Also note that J=|L - S| when a shell is no more than half filled and J=L + S when the shell is over half filled.
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| | yubs
2006-10-29 21:40:11 | Can anyone direct me to a good explanation of the full spetroscopic notation and how it relates to the selection rules?
More specifically, what part of this notation denotes m, the magnetic quantum number? |  |
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