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| Latest 25 Comments | | 10 | Click here to jump to the problem! | dotyhughes117
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| 11 | Click here to jump to the problem! | chavesarlene4
2023-05-10 06:09:37 | Electric charges, magnetic moments, and the electromagnetic field physically interact to form electromagnetism. A wave can form in the electromagnetic field, or it might be static or slowly changing. Light generally refers to electromagnetic waves that follow the principles of optics Grande Prairie Snow Removal |
| 14 | Click here to jump to the problem! | bobbrencher01
2023-05-04 17:41:48 | Maxwell\'s equations are a set of four partial differential equations that describe the behavior of electric and magnetic fields and their interaction with charges and currents, forming the foundation of classical electromagnetism. Is anyone interested to credit repair laredo?\r\n\r\n\r\n\r\n\r\n\r\n |
| 16 | Click here to jump to the problem! | SofiaStirling
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| 17 | Click here to jump to the problem! | emmo
2019-12-18 06:28:15 | According to this solution, \"the cross-product yields 0 force for the two horizontal components,\" but is that right? The field is pointing into the page, which is orthogonal to the line of the induced current, thus there would be force on each horizontal component. This contributes nothing to the net force due to symmetry: the top and bottom horizontal portions of the induced current cancel one another out. |
| 18 | Click here to jump to the problem! | alwayswright5214
2019-12-02 13:39:56 | Compton effect (Compton, 1923), named after its discoverer, the greatest photon energy loss occurs when it is scattered backward (180°) from its original direction. Then, if E is much larger than the rest energy of the electron E0 = me c2 = 0.511 MeV, it is found that the final photon energy E′ is equal to E0/2. www.dc-harvest.com/ |
| 20 | Click here to jump to the problem! | toto212
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| 24 | Click here to jump to the problem! | droosenoose
2019-10-22 23:07:47 | this is a bit misleading because you can easily use negative feedback to amplify signal if you have an op amp and two resistors, which is what I immediately thought of when they said negative feedback.\r\nGuess they were referring to the concept of negative feedback itself, not applications?? |
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