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Latest 25 Comments  0  Click here to jump to the problem!  huanghandage
20190404 20:27:28  We know that the thing is gonna rotate, so eliminate A. Take the derivative of the five solutions, then x\'(0) has to be 2v, so eliminate B, D, and E, and the only choice left is C. 
3  Click here to jump to the problem!  booyah
20190402 05:25:52  I have always thought the \"cyclotron frequency\" referred to the angular frequency, so I left out the 2pi. I feel like ETS should have made which type of frequency they were referring to in the question statement more clear 
9  Click here to jump to the problem!  andymark
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13  Click here to jump to the problem!  johnbhura1
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14  Click here to jump to the problem!  tdl17
20190105 22:45:55  You can also use dimensional analysis. Whatever that goes into the arc tangent should be purely numerical without any units, and the only answer where this happens is choice A. Vq cancels with mv^2 because they both have units of Joule. L cancels with d because they both have units of length. 
19  Click here to jump to the problem!  webtechcoupons
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20  Click here to jump to the problem!  raytyler
20181101 03:14:57  \\lambda_1 = \\frac{1}{2} + i\\frac{sqrt{3}}{2}\r\n\r\n\\lambda_2 = \\frac{1}{2}  i\\frac{sqrt{3}}{2}\r\n\r\n\\lambda_3 = 1\r\n192.168.0.1 http://19216801help.com/ 
21  Click here to jump to the problem!  raytyler
20181101 03:13:02  1 + i  i is not equal to 0. The eigenvalues are actually 1, \\\\\\\\\\\\\\\\frac{1}{2} \\\\\\\\\\\\\\\\pm \\\\\\\\\\\\\\\\frac{\\\\\\\\\\\\\\\\sqrt{3}}{2}i.\r\n192.168.0.1 login 
24  Click here to jump to the problem!  TypT
20181026 22:10:37  Quick, dumb way I did it without having to figure out what exactly the question was asking:\r\n\r\nSpace time intervals have a Pythagorean relationship, the two numbers we are given are 3 and 5, to complete the Pythagorean triple we need a 4 so we get (C). It even has the trap answer of (E), to give a little more confidence in (C). 




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