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0 Click here to jump to the problem!
casseverhart13
2019-09-20 02:00:25
It\'s my pleasure to find this amazing problem who provides mostly unseen information about every single problem which is i really like it. tree trimming
1 Click here to jump to the problem!
casseverhart13
2019-09-19 02:59:13
Some of your problem are actually sounds great. magician
2 Click here to jump to the problem!
casseverhart13
2019-09-17 03:26:45
It was nice of you to provide this timely problem - just what I needed. click here
3 Click here to jump to the problem!
fredluis
2019-09-17 02:10:41
Sounds interesting enough; maybe I\'ll watch out for this kind of solution. carpet cleaners
4 Click here to jump to the problem!
fredluis
2019-09-17 02:05:02
The solution given above is wrong. Purely qualitatively, by Ampere\'s Law, B field will be in the +/- Z direction at point P. The energy flux vector S points outward (obviously). Thus E is in the XY plane (Orthogonal Triad). tree removal
5 Click here to jump to the problem!
fredluis
2019-09-17 02:01:31
Opposite sides of the cube have the same potential, so as we go across the cube we start with the potential at V and end with the potential at V. Since there are no charges inside, there is nothing to change the potential so it must be constant all the way across. tree removal
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fredluis
2019-09-17 01:57:42
This is such an interesting solution i really like the way you solve it. carpet cleaners
7 Click here to jump to the problem!
fredluis
2019-09-17 01:54:27
does it depend on interger or fractional quantum hall effects? tree removal
8 Click here to jump to the problem!
fredluis
2019-09-17 01:52:06
Well, resolving such issues is important because of many reasons carpet cleaners
9 Click here to jump to the problem!
casseverhart13
2019-09-16 04:53:24
Not too many people would actually think about this the way you just did. click here
10 Click here to jump to the problem!
fireballs
2019-09-13 14:18:36
Here\'s an even simpler solution. You know that for an elliptical orbit, the speed of the body is: \\sqrt{\\frac{GM}{R}}<v< \\sqrt{\\frac{2GM}{R}} Assume for the sake of argument that Jupiter\'s velocity saturates the lower bound here, i.e. that it is a circular orbit and v_j = \\sqrt{\\frac{GM}{R}}. Then the speed of the spacecraft is \\frac{3}{2} v_j = \\frac{3}{2}\\sqrt{\\frac{GM}{R}} = \\sqrt{\\frac{9GM}{4R}} > \\sqrt{\\frac{2GM}{R}}\r\n\r\nSo the orbit must be hyperbolic.
11 Click here to jump to the problem!
danielsw98667
2019-09-13 13:04:14
I must try solving it your way. electrical company in jacksonville
12 Click here to jump to the problem!
danielsw98667
2019-09-13 12:56:02
The answer is A. cash loans south africa no credit check
13 Click here to jump to the problem!
danielsw98667
2019-09-13 12:38:29
This is my waterloo. tiny tower laptop stand
14 Click here to jump to the problem!
danielsw98667
2019-09-13 12:27:26
Yeah B is the correct answer. fleck water softener
15 Click here to jump to the problem!
danielsw98667
2019-09-13 12:17:07
I totally agree with you. social security card replacement
16 Click here to jump to the problem!
casseverhart13
2019-09-13 07:54:17
Simply desire to say your problem is amazing. click here
17 Click here to jump to the problem!
camcam
2019-09-12 16:14:14
It looks like a printing error, there are similar dots all over the page if you look closely. That one\'s just in an unfortunate spot, I guess.
18 Click here to jump to the problem!
camcam
2019-09-12 15:46:59
I think there\\\\\\\'s a bit of confusion here between states of even n (like the question states) and even functions (where the prob. density is symmetric around the center of the well).
19 Click here to jump to the problem!
casseverhart13
2019-09-12 05:16:11
Things like this are useful to solve. Gainesville Tree Pro Kensington
20 Click here to jump to the problem!
emergency
2019-09-10 13:27:43
Before the collision, the COM lies on the middle line, L=mvr where r=0 so L=0
21 Click here to jump to the problem!
casseverhart13
2019-09-10 06:12:15
I enjoyed to find this problem. I like your point of view about this. kitchen remodeling Raleigh
22 Click here to jump to the problem!
casseverhart13
2019-09-09 09:44:15
A great problem and a very explicit information of problem to solve for everyone. electrician Orlando
23 Click here to jump to the problem!
Ryry013
2019-09-07 03:00:37
I fell for this trap by thinking of killing ants with a magnifying glass. But here\'s the difference in my opinion (correct me if I\'m wrong). When the oven normally emits radiation from it\'s 600° interior, it goes in many directions and not all the radiation hits our target object, so maybe it only reaches 100°C. Then we put a magnifying glass and, oh my! It\'s all reaching our target object. All our 600° radiation beams are reaching our target object. Now it\'s super 600°! But still only 600°... \r\n\r\nAnother example: just put the target object in the oven, get it too 600°. Thermal radiation is oversaturated, there\'s no way to get \"more\" energy. So if you try to put a magnifying glass inside the oven, it\'s not going to magically amplify the inside of the oven past what it already is.
24 Click here to jump to the problem!
casseverhart13
2019-09-06 05:46:42
Thank you a bunch for sharing this with all people you actually know what you are talking approximately! Bookmarked. house painting
 
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