GREPhysics.NET
GR | #

Login | Register
   
  Latest comments
Latest 25 Comments
0 Click here to jump to the problem!
NoPhysicist4
2017-03-23 14:53:40
Do not mix infinite square well and harmonic potential as I did. In the first case, the numbering starts from 1, while the latter employs 0 as the initial state. Therefore the correct answer is E.
1 Click here to jump to the problem!
dipanshugupta
2017-03-23 14:14:43
Isn\\\\\\\'t the charge outside the region magnetic field is incident?
2 Click here to jump to the problem!
NoPhysicist3
2017-03-23 13:29:00
yes, he should have said \"throw out A\"\r\nwhy would it be o.5? It is 2.
3 Click here to jump to the problem!
NoPhysicist3
2017-03-23 13:24:06
best remark!
4 Click here to jump to the problem!
NoPhysicist3
2017-03-23 12:37:05
The distance considered in mgh is the center of mass, therefore in this problem \\delta h is 5 meters. Thus, the difference in energy is mg\\delta h = 1000 J.
5 Click here to jump to the problem!
NoPhysicist3
2017-03-23 12:31:21
The words \"certain region\" are VERY confusing. However, when choosing between B and E, one should keep in mind that it is unlikely for ETS to consider a correct answer containing ultimate statements. Therefore B is the only correct.
6 Click here to jump to the problem!
NoPhysicist3
2017-03-23 12:23:03
This is very good, however this is not what ETS wants.
7 Click here to jump to the problem!
NoPhysicist3
2017-03-23 10:25:19
Amazing solution
8 Click here to jump to the problem!
NoPhysicist3
2017-03-23 10:16:50
Capacitors in series, the same as resistors in parallel
9 Click here to jump to the problem!
NoPhysicist3
2017-03-23 10:14:23
They stopped doing this after the cheating in china was revealed.
10 Click here to jump to the problem!
NoPhysicist3
2017-03-23 10:13:45
Notice that the total resistance of the smallest circuit is 20 ohms. Therefore total resistance of the right vertical bar is 50 ohms, which is the same as R2. Since the current distributes between R2 end effective R (combined from R3, R4, R5) equally, we imply that the maximum current is at the R1, and therefore the maximum power is.
11 Click here to jump to the problem!
NoPhysicist3
2017-03-23 09:44:14
I love yosun
12 Click here to jump to the problem!
NoPhysicist3
2017-03-23 09:42:00
but as i noticed GRE problems tend to use all information given in the task
13 Click here to jump to the problem!
NoPhysicist3
2017-03-23 09:38:59
same sh*t man
14 Click here to jump to the problem!
NoPhysicist3
2017-03-23 08:42:15
Taking limits in this task is a perfect way to solve the problem (and I think it is what GRE wants to test here), however it could be complicated to guess the factor of 2 between C and D.\r\nMore explicit reasoning is the following: since we have two triangle wedges, the big mass M would be distributed between both, therefore the maximum mass M would be twice of that in answer C, therefore leaving us with the correct D.\r\n
15 Click here to jump to the problem!
dipanshugupta
2017-03-22 14:15:07
Well A looked more beautiful.
16 Click here to jump to the problem!
NoPhysicist2
2017-03-19 11:36:32
http://quantummechanics.ucsd.edu/ph130a/130_notes/node422.html
17 Click here to jump to the problem!
NoPhysicist
2017-03-16 09:44:16
what the heck man are you typing here
18 Click here to jump to the problem!
NoPhysicist
2017-03-16 09:41:16
Why would you consider field to the right of the plane?
19 Click here to jump to the problem!
godkun1
2017-03-15 17:33:04
Just an empty????
20 Click here to jump to the problem!
godkun1
2017-03-15 17:32:25
you are completely right......this is really bad.....
21 Click here to jump to the problem!
godkun1
2017-03-15 17:29:41
You are right
22 Click here to jump to the problem!
blacksheep
2017-03-08 00:23:16
It took me a second to grasp her meaning, too. She\'s just saying that obviously air molecules at a normal density (\"room conditions\") aren\'t packed into a volume of space with literally no room between molecules. The scale (the \"size\") of atoms and molecules is on the order 10^-10 meters (whereas atomic nuclei are on the scale of 10^-14 meters or so), so the \"packing\" of air molecules in the volume of space has to be on a higher scale or else they couldn\'t move at all. Since mean free path has to do with the distance air molecules travel between collisions, it too has to be on a higher scale. Only answers A and B satisfy this requirement.
23 Click here to jump to the problem!
varsha
2017-02-21 11:20:22
Either the question is wrong or there is a typo in the answer, it is v0 = 1/2 Rw0 and not v0 = 1/2 R2 w02.
24 Click here to jump to the problem!
varsha
2017-02-21 11:15:10
Either the question is wrong or there is a typo in the answer, it is v0 = 1/2 Rw0 and not v0 = 1/2 R2 w02.
 
The Sidebar Chatbox...
Scroll to see it, or resize your browser to ignore it...