Latest comments


Latest 25 Comments  0  Click here to jump to the problem!  toto212
20191116 05:06:24  Hello , i Just want to say that, umm..\\\\r\\\\nwhat u make is very amazing and i also like it ^.^\\\\r\\\\nThanks friend. I hope i can see your various works.\\\\r\\\\nKeep working guys. jayatogel 
4  Click here to jump to the problem!  droosenoose
20191022 23:07:47  this is a bit misleading because you can easily use negative feedback to amplify signal if you have an op amp and two resistors, which is what I immediately thought of when they said negative feedback.\r\nGuess they were referring to the concept of negative feedback itself, not applications?? 
7  Click here to jump to the problem!  PHYSGOGO
20191022 04:40:35  oh sorry guys, I found another way: The energy to remove 2 electrons(79.0)= remove 1st+remove 2nd. Since remove 1st is under help of second electron\'s repel force. Removing second is 2^2*13.6=54.4 remove 1st=7954.4=24.6 
8  Click here to jump to the problem!  PHYSGOGO
20191022 04:34:15  since there are interaction between two electrons. we can solve in this way: STEP1： Remove two electrons(79eV) STEP2: pull one electron back(13.6*2^2=54.4eV) the result is also equals: ionize one electron. \\\\r\\\\nThe trick is, we can just calculate ionize energy of isolated electron, so we have to find a way isolate them. \\\\r\\\\nThe result is: 7954.4=24.6 (we set remove is plus,pull back is minus) 
24  Click here to jump to the problem!  Ryry013
20191019 12:36:04  Man this site is buggy. Looked alright in the preview! Basically, it was V is proportional to dB/dt which is about equal to ΔB/Δt. There\'s 3 ΔB per revolution (as in, min>max, changing from N>S), so if we multiply (10 rotations/second)(3 ΔB/rotation) we get 30 ΔB/second 




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