GR 8677927796770177 | # Login | Register

GR9277 #2
Problem
 GREPhysics.NET Official Solution Alternate Solutions
\prob{2}
The longest wavelength x-ray that can undergo Bragg diffraction in a crystal for a given family of planes of spacing d is

1. d/4
2. d/2
3. d
4. 2d
5. 4d

Atomic$\Rightarrow$}Bragg Diffraction

Recall the Bragg Diffraction dispersion relation,

$\lambda = 2d\sin\theta,
$

thus the maximal wavelength $\lambda$ would be $2d$, choice (D). (One can derive that even if one does not remember the formula. Consider two lattice planes. View them from the side so that they appear as two parallel lines. A wave would hit the both planes at, say, an angle $\theta$ from the normal. The wave that reflects off the bottom lattice will have to travel an extra distance, relative to the wave hitting the top plane, equal to $2d\sin\theta$.)

Alternate Solutions
 There are no Alternate Solutions for this problem. Be the first to post one!
 pam d2011-09-27 14:21:19 Yeah, like gt2009, I would just like to reiterate how important it is that the angle in the Bragg relation is the glancing angle, NOT the angle from the normal.Reply to this comment gt20092009-06-14 13:31:29 $\theta$ is the glancing angle, not the angle from the normal (or just use cosine instead of sine).Reply to this comment

This comment is best classified as a: (mouseover)
Mouseover the respective type above for an explanation of each type.

Bare Basic LaTeX Rosetta Stone

LaTeX syntax supported through dollar sign wrappers $, ex.,$\alpha^2_0$produces $\alpha^2_0$. type this... to get...$\int_0^\infty$$\int_0^\infty$$\partial$$\partial$$\Rightarrow$$\Rightarrow$$\ddot{x},\dot{x}$$\ddot{x},\dot{x}$$\sqrt{z}$$\sqrt{z}$$\langle my \rangle$$\langle my \rangle$$\left( abacadabra \right)_{me}$$\left( abacadabra \right)_{me}$$\vec{E}$$\vec{E}$$\frac{a}{b}\$ $\frac{a}{b}$

The Sidebar Chatbox...
Scroll to see it, or resize your browser to ignore it...