GR9277 #1



Alternate Solutions 
casseverhart13 20190704 10:57:43  Thanks for your post! electrical contactor\r\n   tera 20060821 02:14:34  You can get the result by dimentional analysis  

Comments 
casseverhart13 20190704 10:57:43  Thanks for your post! electrical contactor\r\n   deepblue 20130304 18:35:26  This website is great.
I was wondering if there was a possible miscalculation.
It appears using the momentum operator normally defined you would have
(i)*(i)hk which leads to an imaginary number times an imaginary number which is 1 .
So you have  [(i)*(i)] = ()(1)hk. So you get answer (C) which is just hk.
=================================================
(My point is the author divided by (i) in the definition of the momentum operator instead of multipling the two imaginary numbers)
zeper 20130309 09:11:39 
no there is no mistake...1/i means i...which is the same notation you mensioned.

  grep 20061030 13:28:58  You can also recognize that the wave function is just a standard transverse wave (like a light wave) for which de Broglie tells us h=lambda*p and the propagation number tells us k=2 pi/lambda
roofsing 20100621 23:37:57 

  grep 20061003 12:37:48  Oops, I meant it also leaves choice D
BerkeleyEric 20100531 15:18:12 
(D) actually gives units of kg * m/s^2, not kg * m^2/s as needed. (A) cannot be eliminated from dimensional analysis, but from physical intuition we know that a wave traveling in the xdirection should have momentum in the xdirection.

  grep 20060828 13:07:27  Hmm, doesn't dimensional analysis leave C as a possible choice? (or A for that matter)
gina4eva 20111110 18:10:14 
but isn't c the answer?

  tera 20060821 02:14:34  You can get the result by dimentional analysis
alemsalem 20100924 08:30:20 
the units for choice D also work but we dont know that the particle is moving with speed of light.

Quark 20111025 12:04:21 
More accurately, the particle can't be moving at the speed of light.

myscifilullaby1 20120308 17:32:19 
indeed! dimensional analysis gives two possibilities, A & C. When you use the momentum operator, you get C as the final answer.

  gottlob 20060613 12:18:50  I am a physics teacher from Greece and am trying to download the gre.pdf forms of the gre tests. I have downloaded the GRE0177 but i can't get the others (GRE9677, GRE9277 etc. My email is nchalk@phs.uoa.gr. Please, if any one can sent me, or give me information about, the tests i would be gratefull to him.  

Post A Comment! 

Bare Basic LaTeX Rosetta Stone

LaTeX syntax supported through dollar sign wrappers $, ex., $\alpha^2_0$ produces .

type this... 
to get... 
$\int_0^\infty$ 

$\partial$ 

$\Rightarrow$ 

$\ddot{x},\dot{x}$ 

$\sqrt{z}$ 

$\langle my \rangle$ 

$\left( abacadabra \right)_{me}$ 

$\vec{E}$ 

$\frac{a}{b}$ 





The Sidebar Chatbox...
Scroll to see it, or resize your browser to ignore it... 

