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GR8677 #78 |
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Alternate Solutions |
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Comments |
thebigshow500 2008-10-14 01:41:19 | So what will happen if radiation involves? I can't get a concise answer from this case. Anyone care to explain?
Poop Loops 2008-11-05 21:21:34 |
Makes things a lot harder. Charged particles radiate when they accelerate or decelerate. Things with mass accelerate or decelerate under a force. So they'd be pushing each other away and radiating, etc. So it's weird.
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|  | grae313 2007-10-07 18:34:19 | Yosun, you assume the particle with a velocity is moving towards the stationary particle, but what if it was moving away from the particle? The answer must be valid for both cases (moving towards the particle, or away), and in the case where it moves away, potential energy will always be zero and the total energy will just be given by the positive kinetic energy. Thus, C is clearly the answer. |  | dbiggerstaff 2005-11-10 00:13:03 | There\'s a simpler way to look at it: the problem says that each particle initially has zero potential energy, but that one particle has a velocity relative to the other, which implies that it will have some kinetic energy in this reference frame. This means the total initial energy is T+U = (something)+0 = (something positive.) Since there\'s no radiation, energy will be conserved, and the total energy will remain (something positive.) Thus, the correct answer is (c).
nitin 2006-11-16 13:36:49 |
Thumbs up mate!
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