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GR8677 #53 |
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Alternate Solutions |
ee7klt
2005-11-11 04:54:58 | hi,
since oscillations happen only in the x-y plane, the E-field vector thus cannot have components in the z-direction. This eliminates (A) and (B).
The minimum occurs when you're looking directly down the x-axis i.e.  (all you see is the infinitesimal tip of the field vector which doesn't look like it'll generate any waves coming towards you) - this eliminates (D). From here, I guess you'll need to remember that the field goes as  to narrow it further down to (C). |  |
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Comments |
a19grey2
2008-11-03 22:14:06 | I recommend just learning what the picture of an oscillating dipole looks like. rnhttp://en.wikipedia.org/wiki/DipolernrnIt'll help you later in your physics life anyway...
physicsisgod
2008-11-05 20:32:44 |
Here's a cool video of it:
http://www.vis.uni-stuttgart.de/ufac/dipole/
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|  | jw111
2008-09-14 11:09:42 | You see the maximum OSCILATION of charge when you stand on y axis, and minimum oscilation when you stand on x axis.
=> max field take place on y axis
the ocilation is on x-y plane, the field line wave mainly on x-y plane.
=>oscilating field on x-y plane | | ee7klt
2005-11-11 04:54:58 | hi,
since oscillations happen only in the x-y plane, the E-field vector thus cannot have components in the z-direction. This eliminates (A) and (B).
The minimum occurs when you're looking directly down the x-axis i.e. (all you see is the infinitesimal tip of the field vector which doesn't look like it'll generate any waves coming towards you) - this eliminates (D). From here, I guess you'll need to remember that the field goes as to narrow it further down to (C). | | physicsDen
2005-11-09 22:04:58 | is it me, or is this a poor attempt at a solution?
alpha
2005-11-09 22:15:19 |
it's a quick and dirty way to arrive at the right answer.
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