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GR8677 #41 |
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Problem
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Atomic }Binding Energy
Nickel and Iron are the most tightly bound nuclei, thus have the highest binding energy. Nickel isn't on the list, thus Iron must be the choice.
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Alternate Solutions |
Blake7 2007-07-23 17:44:43 | what if Iron wasn't on the list either?
I'm eyeballing a chart (Fig 13-3) in Anderson 'Intro to Modern' (p244) and it shows a curve with a rather flat, totally asymmetric peak of just under about 9MeV per at about A = 60 to 70, so to me that's from about Iron to Gemanium. (how am I to come up with 'the most abundant isotope'?)
Fortunately for us, Iron (C) is 'clearly' the only choice in this band. No doubt there's actually a relation defining this curve. (somewhere)
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Comments |
evanb 2008-06-19 18:54:31 | A and B can be ruled out, or stars wouldn't frequently create many of the elements we enjoy in abundance on Earth.
D and E can be ruled out, because the binding energy is so low that they decay spontaneously. |  | Blake7 2007-07-23 17:44:43 | what if Iron wasn't on the list either?
I'm eyeballing a chart (Fig 13-3) in Anderson 'Intro to Modern' (p244) and it shows a curve with a rather flat, totally asymmetric peak of just under about 9MeV per at about A = 60 to 70, so to me that's from about Iron to Gemanium. (how am I to come up with 'the most abundant isotope'?)
Fortunately for us, Iron (C) is 'clearly' the only choice in this band. No doubt there's actually a relation defining this curve. (somewhere)
FortranMan 2008-10-26 14:18:56 |
, where is the difference between the total mass of the element if it was separated into its correct number of protons and neutrons and its atomic mass. Literally,
m_{n} - W)
note M = W*, where the * operator rounds the number to an integer.
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FortranMan 2008-10-26 14:24:47 |
incomplete post of mine there. = binding energy per nucleon, =mass of a proton, = mass of a neutron, A = atomic number, W=atomic weight, M = atomic mass number (the integer value of W). Thankfully ETS isn't expecting you to be a chemist.
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