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GR8677 #31
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Problem
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Quantum Mechanics }Photoelectric Effect
Perhaps one recalls the ``hot phrase" stopping potential. The used in the photoelectric equation is essentially the stopping potential (energy). This memory-recall immediately narrows the choices down to just (A) and (C). Now, to find out if the potential is positive or negative.
FYI: The Photoelectric effect equation is basically just conservation of energy. One has , where is the kinetic energy of the electron as it accelerates through the medium between the cathode and collector, is the energy to free the electron from the metal, and is the energy given by the light source. Essentially, the energy from the photon first frees the electron from a sort of (valence) electron sea it lives in while in the metal, and then the excess energy propels it from cathode to collector in order to keep the current running. The minimum kinetic energy required to get the current going is the stopping potential (energy) . (According to the fight analogy below, the photon is the one who starts the fight, socking the electron off and away across the currents...)
The electron charge is negative and the potential must be a negative quantity in order to make positive overall.
(On the lighter side... The Photoelectric effect is also related to the Compton Effect. The effects can be seen as an arena fight. Think WWWF, but with electrons and photons. In PEE, the photon knocks the electron out, while in CE, the electron retaliates! It knocks the photon off course.)
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Comments |
spacemanERAU 2009-10-15 09:10:35 | Why does eV have to be positive overall? doesnt the absolute value take care of that?
kroner 2009-10-16 10:43:22 |
There is no "negative value of at which the current stops." Any negative voltage would attract all the free electrons so there would always be a current.
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|  | FortranMan 2008-10-19 15:50:26 | Was the question in error in saying hv instead of hf?
FortranMan 2008-10-19 16:11:28 |
my bad, latex fooled me into thinking it was v, and so did the test >:(
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|  | phys2718 2008-10-16 10:58:57 | Logically, the value of the potential at which the current stops is the same as the value of the potential at which the current starts, depending only on whether you approach it from above or below. This is a stupid question.
justguessing 2009-10-04 06:43:05 |
right, but it says in the question "(...) is initially zero and is then (...) decreased" ... so you know youre coming from the right side. I missed that one, too; because I'm used to read from left to right. Totally agree: Stupid question!
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|  | erc 2005-11-03 14:50:58 | Do you perhaps mean "narrows the answer choices down to (A) or (C)" (i.e. not B)?
Thank you for this exceedingly useful site! Please, please post GR0177 solutions in the next few days!
yosun 2005-11-03 20:07:56 |
erc: thanks for the typo note! It has been corrected.
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