GR8677 #28
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Alternate Solutions |
Giubenez 2014-10-22 02:42:06 | The only way to solve this problem is to remember the first Spherical Harmonics, or, at least, their dependence to .
In fact, using the conventional coordinates where is the polar angle and is the azimutal angle, they always have a term
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The direction is to estimate A, we have thus to integrate on that in the question is CAPITALIZED and we have to choose the interval | |
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Comments |
fredluis 2019-08-09 04:33:09 | This problem is deceptively simple, people. Remember that if the charge is moving towards the wire its velocity vector would be negative. tree removal | | joshuaprice153 2019-08-09 02:42:01 | I had found that the information is very helpful. That’s a awesome article you posted.I will come back to read some more. towing service | | Giubenez 2014-10-22 02:42:06 | The only way to solve this problem is to remember the first Spherical Harmonics, or, at least, their dependence to .
In fact, using the conventional coordinates where is the polar angle and is the azimutal angle, they always have a term
.
The direction is to estimate A, we have thus to integrate on that in the question is CAPITALIZED and we have to choose the interval | | alemsalem 2009-09-23 19:47:52 | i think the answer is correct but the it's missing smthing,, how do u know u should integrate over 2 PI u should integrate over one PI and the other half is accounted for by symmetry there are no additional probabilities,, that would compensate for the factor of 2 pauli mentioned
flyboy621 2010-11-14 19:33:17 |
The integration is over all possible values of . Since the given function is periodic, you only need to integrate over the period, which is .
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| | pauli568 2007-10-12 13:48:01 | I think there is no correct answer given here.
The con dition of normalization goes as
\int{psi}dv=1 in which case theta coordinate should aso be taken care of and wich will result in an extra 2.
The result should be \frac{1}{2\sqrt{pi}}
dean 2008-10-09 21:40:08 |
The official solution is essentially correct, though I think it's better to think of the normalization as <|>=1, you get the conjugation for free.
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HaveSpaceSuit 2008-10-17 17:50:12 |
They do not specify a theta dependence for the wave function so you can assume it is only a function of phi. Normalize the given function.
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