|
GR8677 #15
|
|
|
|
|
Alternate Solutions |
| There are no Alternate Solutions for this problem. Be the first to post one! |
|
|
Comments |
ubaraj
2007-11-01 01:15:13 | the volume is 1. There can be no He atoms in the volume 10E-6. So all N atoms have to be within the volume (1-10E-6), and so the probability becomes (1-10E-6)^N. The choice is C!! |  | Furious
2007-08-17 15:40:58 | You really just need to look at the limiting factors in this problem.
When N is 0 the probability should be 1. That eliminates A and D.
When N is extremely high, the probability should go to 0. That eliminates E, (not that any of us thought it was E)
So that leaves us with B and C. Which both match the limiting cases, but just think about it when N is 1. When N is one there should be a very high chance that it is not in the specific 1e-6 area.
For B, the probability is 1e-6, not very high at all.
For C, the probability is 0.99999, pretty close to 1.
This helped me since, I get super confused whenever I think about probability. | | wishIwasaphysicist
2006-01-24 11:27:10 | How did you connect P(Ngasatoms) = (1-1E-6)^N to answer C?
yosun
2006-02-01 22:02:05 |
hi wishIwasaphysicist, because each of the N molecules are independent, the probability would be multiplicative. Thus, if the particle for each particle is P, the probability for N particles would be  .
|
|  |
|
| Post A Comment! |
You are replying to:
You really just need to look at the limiting factors in this problem.
When N is 0 the probability should be 1. That eliminates A and D.
When N is extremely high, the probability should go to 0. That eliminates E, (not that any of us thought it was E)
So that leaves us with B and C. Which both match the limiting cases, but just think about it when N is 1. When N is one there should be a very high chance that it is not in the specific 1e-6 area.
For B, the probability is 1e-6, not very high at all.
For C, the probability is 0.99999, pretty close to 1.
This helped me since, I get super confused whenever I think about probability.
|
Bare Basic LaTeX Rosetta Stone
|
LaTeX syntax supported through dollar sign wrappers $, ex., $\alpha^2_0$ produces  .
|
| type this... |
to get... |
| $\int_0^\infty$ |
 |
| $\partial$ |
 |
| $\Rightarrow$ |
 |
| $\ddot{x},\dot{x}$ |
 |
| $\sqrt{z}$ |
 |
| $\langle my \rangle$ |
 |
| $\left( abacadabra \right)_{me}$ |
_{me}) |
| $\vec{E}$ |
 |
| $\frac{a}{b}$ |
 |
|
|
|
|
|
