GR8677 #10



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NAJUM UDDIN 20170120 04:49:49  THANKS \r\n   varshakr 20161227 10:46:29  depends on units   Giubenez 20141022 02:55:55  Nice bad pics:
the trend for x>R isn't an inverse square (if you estimate for E(x=2R)/E(R) you find 1/2 and not 1/4.
Furthermore it seems to have an horizontal asymptote > 0......
And so, all the graph are wrong.   flyboy621 20101109 20:54:39  A minor correction: the field increases linearly with the radius of the sphere, not the volume. Hence the straight line of graph C.
funnyjokes 20180412 01:48:26 
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  nmast 20091124 09:16:37  Since the charge density is uniform, shouldn't E go like Q enclosed? Being a sphere, this would be like r^3, making D correct.
kroner 20091127 19:08:54 
No. Q is proportional to , but E is proportional to which means E is linear in r, as in choice C.

  wittensdog 20090924 21:45:16  ETS sure does love to throw in unnecessary details  who cares if the charge is positive or negative when it comes to the field magnitude?   Andresito 20060314 22:37:41  Gauss' law E*A = Q/epsilon
Yours is an approximation.
Thanks Yosun.
lxanderl 20090628 17:23:43 
Depends on if he's using cgs or SI

 

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