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GR0177 #93
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Alternate Solutions |
radicaltyro
2006-10-28 23:38:14 | One can also note that this is more or less the definition of the bohr radius. |  |
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Comments |
bhaynor
2009-10-03 12:30:22 | I get C. It asks for the most probable value of r, not the expectation value of r. The most probable value of r occurs when Psi is maximized, at r = 0.
bhaynor
2009-10-03 12:32:07 |
Ignore my last comment. I forgot about r^2.
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|  | anmuhich
2009-03-17 13:09:47 | You can also remember that in general lower energy states are more probable and that the lowest energy state of hydrogen is the ground state at the bohr radius. | | Imperate
2008-10-04 14:52:04 | An interesting note on this question, is that the most probable value of r for the ground state wavefunction, is NOT equal to the expectation value.rnrnThe expectation value is actually 1.5a_o.rnrnhttp://hyperphysics.phy-astr.gsu.edu/hbase/quantum/hydr.html#c3rnrnshows nice solutions to both of these related problemsrnrn | | radicaltyro
2006-10-28 23:38:14 | One can also note that this is more or less the definition of the bohr radius.
mitama
2008-08-09 17:56:58 |
Depending on the wavefunction, this may or may not be true (luckily, in this case it is). It's probably best to go through the work just to be sure.
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syrock
2009-10-08 16:50:41 |
yeah, hydrogen.... bohr.... come on its gatta be a0
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| | jax
2005-11-30 19:03:20 | Why does dV become  ? Isn't that the surface area ?
yosun
2005-11-30 20:19:06 |
jax: thanks for the typo alert; the typo's been fixed:  . (The radial probability distribution  is related to the probability  by  .)
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