GR0177 #79



Alternate Solutions 
Deafro 20120124 15:45:45  E^2=sqrt(p^2*c^2+(m*c^2)^2)
E=10 GeV
p=8 GeV/c
mc^2= rest energy
Rearrange the formula and solve for mc^2.   mike 20091106 18:34:27  Another way of doing it:
and
. Multiply the first eqn by and divide the two to get:
Plug in to to find .
Plug back in to the momentum equation:
thus .
I omit units, but it should be easy enough to follow. It seems a little longer, but its much less thinking once one remembers the relativistic energy/momenta equations.   Ning Bao 20080201 07:43:40  Set c=1 > pythagorean triple.  

Comments 
Deafro 20120124 15:45:45  E^2=sqrt(p^2*c^2+(m*c^2)^2)
E=10 GeV
p=8 GeV/c
mc^2= rest energy
Rearrange the formula and solve for mc^2.   mike 20091106 18:34:27  Another way of doing it:
and
. Multiply the first eqn by and divide the two to get:
Plug in to to find .
Plug back in to the momentum equation:
thus .
I omit units, but it should be easy enough to follow. It seems a little longer, but its much less thinking once one remembers the relativistic energy/momenta equations.   astrodoo 20080917 01:38:23  manasi, the value of 64 (< the square of momentum) has a dimension of , so you can easily catch the yosun's solution if you consider the dimension of each terms.   Ning Bao 20080201 07:43:40  Set c=1 > pythagorean triple.   Gaffer 20071024 08:42:58  There is a typo in the soln, which is why manasi is confused. Yosun used the to cancel the GeV/c in the momentum. But then she pulled it out again inthe next line.
No biggie.
It should go:
Plugging the momentum into the first equation, one has
and then continue as she concludes   manasi 20070928 12:05:48  hi, if i m not mistaken shudnt it be ????
hope it appears rite m new to latex!!
hey thanks a lot yosun.. ur solutions are very helpful!! :)
astrodoo 20080917 01:46:59 
manasi, the value of 64 (< the square of the momentum) has a dimension of , so you can easily catch Yosun's solution in which term is disappeared if you look dimensions of each term.

 




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