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Statistical Mechanics}Maxwell-Boltzmann Distributions

The Maxwell-Boltzmann distribution is N\propto g e^{-\epsilon/(kT)}, where g is the degeneracy.

Given \epsilon_a = 0.1+\epsilon_b, one finds the ratio of distributions (thus ratio of numbers) to be e^{-(0.1+\epsilon_b)/kT}/e^{-\epsilon_b/kT}= e^{-0.1/kT}.

The problem gives kT = 0.025 eV, and thus the above ratio becomes e^{-.1/.025}=e^{-4}, as in choice (E).


See below for user comments and alternate solutions! See below for user comments and alternate solutions!
Alternate Solutions
Ning Bao
2008-02-01 07:39:44
Quick elimination: higher states are less likely->D or E.

Ratio of given energy to kT mist be important: as Energy of A increases, likelihood in state A decreases ->E.
Alternate Solution - Unverified
Comments
Ning Bao
2008-02-01 07:39:44
Quick elimination: higher states are less likely->D or E.

Ratio of given energy to kT mist be important: as Energy of A increases, likelihood in state A decreases ->E.
Alternate Solution - Unverified

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