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GR0177 #3
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Problem
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This problem is still being typed. |
Mechanics }Kepler's Third Law
Recall Kepler's Third Law stated in its most popular form, The square of the period is proportional to the cube of the orbital radius. (Technically, the orbital radius is the semimajor axis of the ellipse.)
Recast that commonsense fact above into equations to get  , as in choice (D).
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Alternate Solutions |
nathan12343
2008-08-13 13:44:56 | One can always remember that
And, from the Virial Theorem,
From this we get
Now, the orbital Period,  , is nothing but
So, we have,
Which is the answer |  |
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Comments |
nathan12343
2008-08-13 13:44:56 | One can always remember that
And, from the Virial Theorem,
From this we get
Now, the orbital Period, , is nothing but
So, we have,
Which is the answer | | michealmas
2007-01-01 16:00:24 | That's an elegant way to solve it, but if you didn't remember it, you could equate the forces, Newtons Law of Gravitation with the centripetal force for uniform circular motion:
using
and
 . |  |
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