GR8677 #28



Alternate Solutions 
Giubenez 20141022 02:42:06  The only way to solve this problem is to remember the first Spherical Harmonics, or, at least, their dependence to .
In fact, using the conventional coordinates where is the polar angle and is the azimutal angle, they always have a term
.
The direction is to estimate A, we have thus to integrate on that in the question is CAPITALIZED and we have to choose the interval  

Comments 
fredluis 20190809 04:33:09  This problem is deceptively simple, people. Remember that if the charge is moving towards the wire its velocity vector would be negative. tree removal   joshuaprice153 20190809 02:42:01  I had found that the information is very helpful. Thatâ€™s a awesome article you posted.I will come back to read some more. towing service   Giubenez 20141022 02:42:06  The only way to solve this problem is to remember the first Spherical Harmonics, or, at least, their dependence to .
In fact, using the conventional coordinates where is the polar angle and is the azimutal angle, they always have a term
.
The direction is to estimate A, we have thus to integrate on that in the question is CAPITALIZED and we have to choose the interval   alemsalem 20090923 19:47:52  i think the answer is correct but the it's missing smthing,, how do u know u should integrate over 2 PI u should integrate over one PI and the other half is accounted for by symmetry there are no additional probabilities,, that would compensate for the factor of 2 pauli mentioned
flyboy621 20101114 19:33:17 
The integration is over all possible values of . Since the given function is periodic, you only need to integrate over the period, which is .

  pauli568 20071012 13:48:01  I think there is no correct answer given here.
The con dition of normalization goes as
\int{psi}dv=1 in which case theta coordinate should aso be taken care of and wich will result in an extra 2.
The result should be \frac{1}{2\sqrt{pi}}
dean 20081009 21:40:08 
The official solution is essentially correct, though I think it's better to think of the normalization as <>=1, you get the conjugation for free.

HaveSpaceSuit 20081017 17:50:12 
They do not specify a theta dependence for the wave function so you can assume it is only a function of phi. Normalize the given function.

 




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