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GR9677 #73
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Alternate Solutions |
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Comments |
archard
2010-05-30 13:30:19 | Once you see that you have an integrand  , you can pretty much bet that the answer is C since it's the only one with a  in the denominator. |  | Inri
2010-04-09 23:29:04 | You can immediately eliminate (D) and (E) by knowing that the numerator can't depend that way on gamma, as it produce the wrong units for anything but gamma = 0. You can immediately eliminate (A) by knowing that the work depends on the initial pressure and volume.
You can eliminate (B) by knowing that the sum of the pressures shouldn't affect the final work (though the difference might).
That leaves option (C).
Fortunately, the integral is not too difficult and in this problem you only need to get so far as the constant ) or ) as there is only one option with that constant. | | a19grey2
2008-10-30 21:07:21 | If we plug in C's dependence on V later in the problem, why can we ignore this dependence when doing the integral?
gt2009
2009-07-03 12:35:10 |
C is a constant so you can pull it out of the integral. It is not ignoring anything.
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| | physicsisgod
2008-10-30 15:07:48 | It took me a minute to realize how  , so in case anyone else has this problem:
Tada! Thanks, ETS, for putting the correct answer in the most laborious form possible!
AER
2009-03-31 17:15:29 |
Thankfully, once you get the  factor, you're done.
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sullx
2009-11-03 18:54:33 |
Yeah. After I saw the factor I was confident of C.
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