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GR9677 #36
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Special Relativity}Conservation of Energy

The rest mass for each mass is 4kg. They collide head-on with identical speeds pointing in opposite directions. This implies that the composite mass is at rest. Thus, recalling that the total energy is given by and that the rest mass is given by , one has
, where M is the composite mass.

The particle travels at , which yields . Plug this in to get .  Alternate Solutions
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CaspianXI
2009-03-22 16:24:17
The two lumps' energies will be "converted" into mass when they collide and stop because we're given that no energy is radiated. Hence, the final mass must be greater than 8 kg. So, we can immediately eliminate options (A), (B), and (C).

So, if you can't figure it out, you can guess and have a 50% chance of getting it right. lowder.chris
2007-10-03 21:31:57
Relativity gives me a headache. :)
 bbaker032007-10-16 18:38:25 sorry im looking at the solution and getting confused. are you using the equation =
 grae3132007-10-31 12:44:17 yes, bbaker03, if you plug in to the equation you wrote for gamma, you get
 bbaker032007-11-01 10:24:11 Thanks a lot for your help this site is saving my life on this test. Can't thank you all enough.      LaTeX syntax supported through dollar sign wrappers $, ex.,$\alpha^2_0$produces . type this... to get...$\int_0^\infty\partial\Rightarrow\ddot{x},\dot{x}\sqrt{z}\langle my \rangle\left( abacadabra \right)_{me}\vec{E}\frac{a}{b}\$