GR9677 #27


Problem


This problem is still being typed. 
Lab Methods}Log Graphs
Log graphs are good for exponentialrelated phenomenon. Thus (A), (C), and (E) are appropriate, thus eliminated. The stopping potential has a linear relation to the frequency, and thus choice (B) is eliminated. The remaining choice is (D).


Alternate Solutions 
Izaac 20120821 01:18:44  One can also simply remember that Bode plots (gain VS ) are semilog ones, so obviously D is inappropriate .  

Comments 
Memol 20120918 07:17:56  Can anyone help me with an study reference about these graph stuff?   Izaac 20120821 01:18:44  One can also simply remember that Bode plots (gain VS ) are semilog ones, so obviously D is inappropriate .   keenanman 20071016 12:38:05  In choice D, the graph gain vs 1/frequency is linear. The graph gain vs frequency is hyperbolic.   eshaghoulian 20071002 04:11:09  Just to add a little bit as to why log graphs are good for exponential related phenomena, note that a power law in loglog coordinates is a line:
which is of the form (since is just a constant (like ) and we identify with and with , as these are our new axes in loglog coordinates). So the exponent in the power law becomes the slope in loglog coordinates. Testing this is a GRE favorite, as it is a major tool in experimental physics.
tachyon788 20091006 11:48:47 
You have a small math error in your use of logs. The equation should be:

 

Post A Comment! 

Bare Basic LaTeX Rosetta Stone

LaTeX syntax supported through dollar sign wrappers $, ex., $\alpha^2_0$ produces .

type this... 
to get... 
$\int_0^\infty$ 

$\partial$ 

$\Rightarrow$ 

$\ddot{x},\dot{x}$ 

$\sqrt{z}$ 

$\langle my \rangle$ 

$\left( abacadabra \right)_{me}$ 

$\vec{E}$ 

$\frac{a}{b}$ 





The Sidebar Chatbox...
Scroll to see it, or resize your browser to ignore it... 

