GR8677 #88



Alternate Solutions 
There are no Alternate Solutions for this problem. Be the first to post one! 

Comments 
Giubenez 20141017 02:22:50  Since we know that boson condensate at low temperature (like 4HE) PB must be the lowest pressure.
The only answer that takes consider this possibility is the right one!   kaic 20131009 14:05:52  Electron degeneracy is one reason (along with neutron degeneracy pressure, which is even higher) why stars don't always collapse into a black hole. The more you compress a gas of electrons, they fill up all the energy states in pairs (by the Pauli exclusion principle) and this builds an immense pressure. On the other hand, bosons will all fall to the lowest energy level, and eventually form an BoseEinstein condensate. Since they can all share the same energy state, the pressure they exert as they are compressed is extremely small, as they can keep going to lower energy states instead of pushing back against compression.   asdfuogh 20111106 16:59:03  Don't you hate when you go too quickly and mess up the comparison signs? Alligator eats the bigger one.. :(   pam d 20110926 22:15:19  I just want to point out that all of these insights are really great, but there is always a way to get the question even if you don't have all of the information necessary. Specifically, if you know that bosons have to have contribute the weakest pressure (just think about photons as Almno10 pointed out) then you don't need to know whether or not the Fermi pressure is higher than the classical contribution. Choice (B) is the only one that puts bosons the lowest.
Also, lol @ (A).   Almno10 20101112 18:59:17  I recall that fermi pressure is so ridiculously high, that it is able to keep a star from collapsing under its own gravity. Bosons on the other hand...well, have you ever felt the pressure on your face from sunlight?
NCSUPHYSICS 20120412 20:12:47 
it is called sunburn!

  Bolek 20100409 15:08:48  Just would like to add a captivating factoid. The pressure due to the Pauli exclusion principle for electrons in a metal is so high that you can always treat metals as if they were at 0K!!! Or conversely, the electrons in a metal at 0K behave almost exactly as they do at 300K.   neutrinosrule 20080914 12:40:48  Bosons can occupy the same energy state as each other, where fermions have to obey the pauliexclusion principle. Therefore, at cold enough temperatures, bosons would all be in the lowest energy state and it makes sense that they would have the lowest pressure, while fermions would be all over the place and have a higher pressure. If quantum effects were ignored, it makes sense that that pressure would be in between since fermions and bosons seem to be at two extremes.
jmason86 20090813 20:41:20 
exactly how I did it too.

flyboy621 20101115 19:38:27 
Also, other things being equal, bosons tend to be closer together, and fermions farther apart, than distinguishable particles (which would obey Boltzmann statistics). Thus you would expect lower pressure for bosons and higher pressure for fermions.

 

Post A Comment! 

Bare Basic LaTeX Rosetta Stone

LaTeX syntax supported through dollar sign wrappers $, ex., $\alpha^2_0$ produces .

type this... 
to get... 
$\int_0^\infty$ 

$\partial$ 

$\Rightarrow$ 

$\ddot{x},\dot{x}$ 

$\sqrt{z}$ 

$\langle my \rangle$ 

$\left( abacadabra \right)_{me}$ 

$\vec{E}$ 

$\frac{a}{b}$ 





The Sidebar Chatbox...
Scroll to see it, or resize your browser to ignore it... 

