GR8677 #7


Problem



Mechanics}Statics
Straightforward Newtonian statics:
Divide the two equations above, cancel T's, and get: \par
. Choice A is right.


Alternate Solutions 
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Comments 
JasonHupp 20180730 11:06:29  Seems like every one must remember the formulas to do the sum and get desired answer.\r\nhttp://www.pumpkin.com   pam d 20110923 19:24:15  free points!   Dodobird 20101104 18:15:41  Any solution must involve horizontal and vertical components of force.
Tangents satisfy this requirement.
Because the box weighs 2 kg already we see gravity, the vertical force, will be larger.
Opposite/Adjacent < 1 means that only A satisfies this requirement.
  signminus 20100801 12:15:58  Not quite. The question asks for the angle, . As in the posted solution, we have
.
To invert this equation, we do
,
answer A.
signminus 20100801 12:16:42 
Oops, meant that as a reply to rlorek's comment below.

  rlorek 20100730 12:32:55  This was worked out well, but the answers are looking for "arc" functions which are the inverse of normal trig functions.
The inverse of tan(theta)=0.5 is...
arctan(theta)=2.0
Therefor "C" should be the correct answer.
flyboy621 20101109 20:27:00 
If then .

  belle 20091011 13:50:56  This also solvable with simple geometric tactics
tan(theta)=
using g=10
tan(theta)=.5
  kostas 20070109 12:42:27  I see the answers but I cannot find the questions. Where are they? There was a "jump into the question" buton in the old site that I can't see now
yosun 20070222 19:09:03 
I am in the process of typing up the questions. Currently, only GR8677 is available as graphics file displayed next to the official solution. GR9277 questions will be available shortly, and the rest, eventually.

 

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type this... 
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$\int_0^\infty$ 

$\partial$ 

$\Rightarrow$ 

$\ddot{x},\dot{x}$ 

$\sqrt{z}$ 

$\langle my \rangle$ 

$\left( abacadabra \right)_{me}$ 

$\vec{E}$ 

$\frac{a}{b}$ 





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