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  GR8677 #64
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Verbatim question for GR8677 #64
Electromagnetism}Impedance Matching

Because the capacitor is fully charged, it is the generator. The inductor, which opposes the current as the capacitor discharges, is the load. Impedance matching requires that the impedance of the generator and load are the same. However, since and , for the generator and load, respectively, and and , one finds that for impedance matching, .

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Comments
Marian
2016-01-05 08:57:59
http://http://grephysics.netNEC
Marian
2016-01-05 08:56:56
Neige Hunter: montres, nerds pourrait knock réplique Breitling Bentley Flying B plongée en apnée, il est prêt, durée du rythme cardiaque, mais tout le monde peut être dit de se concentrer sur la conception, \"et alors, regardez cette heure génial !.\"\r\n\r\nreplique " target="_blank">http://www.repliquemontresfr.eu\">replique montreNEC
Marian
2016-01-05 08:56:09
http://www.repliquemontresfr.euNEC
nishamgu
2011-12-19 22:56:11
prove the commutation relation[L_k,r^2]=0 where r is the radius vectorNEC
jw111
2008-09-01 15:11:23
You need to know two things
(1) The impedance is the resistance of object in AC circuit.
(2) The imaginary part of impedance control the PHASE of voltage(cross the object) and current (through the object).

In this problem, we can treat the circuit as an IDEA POWER SOURCE + an OBJECT with impedance equal to

R_g+R_g+jX_g+jX_l

with the max power transfer to the OBJECT
the phase of V and I must be inphase that the imaginary part of effective impedance must be 0.

Thus X_l=-X_g
NEC
RebeccaJK42
2007-03-15 14:22:16
Why is it negative Xg and not positive Xg?
Blake7
2007-09-21 19:18:17
One needs the 'imaginary' reactances to cancel out and thus 'match the impedance'
NEC
sharpstones
2006-10-19 13:49:09
What's this about a capacitor and an inductor? Problem 64 from 86 exams says "An alternating current electrical generator has a fixed internal impedance..." ?Help
yosun
2005-12-06 20:24:53
jax: thanks for the correction. Fixed Typos!
jax
2005-12-02 21:27:25
This one confused me at first so let me clarify,

To maximize the power transfer, the impedance needs to be 'matched'. The impedance is 'matched' if the load impedance equals the complex conjugate of the source impedance, (Z_{load} = Z_{source}^*).

In our case R_g + jX_g = R_g - jX_l maximizes the power transfer, so X_l = - X_g.
jax
2005-12-02 21:28:16
Lots more info here: http://en.wikipedia.org/wiki/Impedance_matching#Complex_conjugate_matching
RusFortunat
2015-10-21 14:21:02
Now it is clear. Thank you
NEC

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