GR8677 #62



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Comments 
deneb 20181010 04:15:46  well damn, didn\'t think about E, I solved the equation and saw \"ln\" so I just picked B lol   lattes 20080806 13:19:11  Another way to solve is considering on the choices. None of them gives so the answer must be (E)
chrisfizzix 20081003 13:21:18 
This man speaks the truth. Solving a DEQ no matter how simple is almost always not the way to go about solving an ETS problem. Boundary conditions are definitely the way to go here.

shak 20100731 13:03:10 
in this problem, boundary condition works very good, right:) and also we can always check solution by initial and boundary condition, and eliminate wrong answers

  Blake7 20070722 20:55:16  Why would someone attempt a "None of the above" problem on a timed record exam? I see that and think "BYPASS" immediately.
Rune 20071014 22:51:00 
Because in this case it is very simple as long as you know the , in which case it takes all of 15 seconds to read and solve.

gliese876d 20081017 11:26:40 
Or because, crazy lunatics like me actually had the eq. for this memorized, so it took 2 seconds to realize the right answer wasn't there :)

neon37 20101103 10:18:31 
None of the above in this was pretty easy to figure but, it was very hard to be quite confident. I must remember use boundary conditions!! It is the way to go for ETS DEQs.

llama 20131016 18:47:14 
Or these days, because you play kerbal space program and have an interest in physics so you know the rocket equation

 

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LaTeX syntax supported through dollar sign wrappers $, ex., $\alpha^2_0$ produces .

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$\int_0^\infty$ 

$\partial$ 

$\Rightarrow$ 

$\ddot{x},\dot{x}$ 

$\sqrt{z}$ 

$\langle my \rangle$ 

$\left( abacadabra \right)_{me}$ 

$\vec{E}$ 

$\frac{a}{b}$ 





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