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GR8677 #37 |
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Alternate Solutions |
spacebabe47
2007-09-30 08:36:46 | For some reason the concept of tension in force diagrams never made much sense to me.
A different way of looking at the problem. Think of the forces as making a right triangle.  forms one leg pointing down,  forms one leg pointing radially outwards, and  forms the hypotenuse along the string.
Thus, 
or ^2+(mg)^2)^{1/2})
^{1/2})
Answer E
|  | eshaghoulian
2007-09-15 05:14:12 | Can be done by limits/units: C/D have incorrect units; in the limit r = theta = 0, A gives you 0 tension (should be mg); B is maximized at theta=0 (gives mg) when, physically speaking, it should be minimized at that point (consider triangle inequality) | |
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Comments |
spacebabe47
2007-09-30 08:36:46 | For some reason the concept of tension in force diagrams never made much sense to me.
A different way of looking at the problem. Think of the forces as making a right triangle. forms one leg pointing down, forms one leg pointing radially outwards, and forms the hypotenuse along the string.
Thus,
or
Answer E
| | eshaghoulian
2007-09-15 05:14:12 | Can be done by limits/units: C/D have incorrect units; in the limit r = theta = 0, A gives you 0 tension (should be mg); B is maximized at theta=0 (gives mg) when, physically speaking, it should be minimized at that point (consider triangle inequality) | | shashiprakash
2007-07-26 00:11:40 | we can eliminate two answers on the basis of units. they are (C) and (D). |  |
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