GR8677 #35



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Comments 
Almno10 20101111 19:34:47  I always think of that skater scott hamilton. He used to do back flips... had tons of energy. Hamiltonian is total energy.
Lagrangian on the other hand? Lagrange multipliers are for lazy people. Hard workers would optimize functions by guess and check (lazy = less energy TV).
whatever.
mpdude8 20120415 21:05:06 
Hey, man, whatever works. I have some weird ways of remembering random crap too.

  a19grey2 20081103 21:24:52  Also, if you are unsure about the sign of the term you can just note that answer B) and D) are exactly equivalent through the relation noted by yosun in the original solution. Thus, ETS would never give TWO right answers and so the correct sign must be the unique answer given in A.
BUT... you really should remember the sign conventions for the Hamiltonian and the Lagrangian.
BerkeleyEric 20100112 21:48:15 
Well, I suppose if they wanted to be really tricky they could have also had an option for (1/2)mv^2+ kx^4 to test if you know that Hamiltonians are in phase space (x, p_x) and Lagrangians are in state space (x, dx/dt).

neon37 20101101 10:46:35 
@BerkeleyEric  that is true but that wouldnt make either of them wrong.
Important thing is to remember that Hamiltonian is total energy of the system where as Lagrangian is not.

  Mexicorn 20051108 12:11:38  Like the last problem, the potential should be
yosun 20051109 02:24:56 
Mexicorn: thanks for the typoalert; it has been corrected.

 

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