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GR8677 #30
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Alternate Solutions |
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Comments |
wittensdog
2009-07-25 17:54:02 | ETS is good at thinking of traps. I almost wanted to go for C. I saw the 4s1 electron being the least tightly bound, and in my mind a connection was made with the number 4. Clearly, l = 4 is supposed to trick you, when of course the electron actually has n = 4, not l = 4. It's value for orbital angular momentum is l = 0, of course.
jmason86
2009-08-16 16:36:12 |
I must have fallen for a trap too. I chose (A) immediately and without hesitation.
I was thinking that the n=3 shell only means the s-subshell. So when I saw that we were given  , I assumed that (A) was correct. However, the n=3 is a total shell consisting of the s, p, and d subshells... If (A) were true then we would be talking about Zinc with [Ar]  .
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|  | kyros
2007-10-30 21:42:24 | Shouldn't that be Sigma_4,0,0, since m can only range from -l to +l anyway? | | simpsoxe
2006-11-30 21:20:14 | well the valence shell is  , but my question is about the other electrons in the lower shells. don't we have to consider them as part of the electron distribution? or do we assume they all have spherically symmetric distributions? (and why would that be?)
Blake7
2007-07-23 18:26:38 |
The lower shells all appear to be completely filled
2 2 6 2 6
if I'm not mistaken that will make them all symmetric
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