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GR0177 #95
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Alternate Solutions |
fcarter
2008-10-13 17:16:57 | Another one where limits are the fast way. For K->1, E->E. For K->inf, E->0. Only answer that satisfies is A. |  | Mexicana
2007-10-02 17:57:24 | Another way to increase your chances of getting it right is by elimination of choices B, C and D since using dimensional analysis only choice A and E have the correct dimensions of electric field (  is dimensionless). If with this you also remember the fact that a dielectric under an applied electric field, induces an internal field so that the total field inside decreases, then only choice A remains (as this is the only one which would decrease the original field  ). | | herrphysik
2006-10-02 18:42:02 | Just use the equation (4.35 in Griffiths)  where  is the relative permittivity. Plug in the given  to get the correct answer. | |
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Comments |
fcarter
2008-10-13 17:16:57 | Another one where limits are the fast way. For K->1, E->E. For K->inf, E->0. Only answer that satisfies is A.
f4hy
2009-11-07 00:27:13 |
Doesn't (B) satisfy those limits as well?
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| | Mexicana
2007-10-02 17:57:24 | Another way to increase your chances of getting it right is by elimination of choices B, C and D since using dimensional analysis only choice A and E have the correct dimensions of electric field ( is dimensionless). If with this you also remember the fact that a dielectric under an applied electric field, induces an internal field so that the total field inside decreases, then only choice A remains (as this is the only one which would decrease the original field ). | | Mexicana
2007-10-02 17:52:53 | Another way to increase your chances of getting it right is by elimination of choices B, C and D since using dimensional analysis only choice A and E have the correct dimensions of electric field ( is dimensionless). |  | herrphysik
2006-10-02 18:42:02 | Just use the equation (4.35 in Griffiths) where is the relative permittivity. Plug in the given to get the correct answer. | |
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