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GR0177 #69
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Alternate Solutions |
ee7klt 2005-11-11 04:25:27 | Hi,
I think E123 has got it right and just wanted to add my 2 cents to this to see if this reasoning is right.
I think the quantity of interest is the optical path length (OPL) where since this is really the distance that the light 'sees'?
Thus for first order constructive interefence at the air/oil boundary, we require giving .
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Comments |
CaspianXI 2009-03-01 19:22:35 | This is minor... but the solution said that . I think the author meant . |  | Poop Loops 2008-11-01 20:29:01 | Okay, so what does the glass have to do with it? Do we just ignore it or what? |  | etano 2007-11-02 10:15:13 | http://physics.bu.edu/~duffy/PY106/Diffraction.htmlrnthis helped me.
etano 2007-11-02 10:15:49 |
http://physics.bu.edu/~duffy/PY106/Diffraction.html
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|  | irishroogie 2007-10-02 14:15:17 | But I thought the formula for constructive interference in thin films was: 2nt = (m+1/2)*lambda, m=0,1,2... and m=0 for minimum thickness.
Using that formula you get 100nm which is clearly none of the answers, but I am confused as to where I am going wrong?
irishroogie 2007-10-02 20:44:06 |
Kk, So my question was flawed. 2nt=m*lambda is correct since the phase changes again by 180 at the oil glass interface. Woops!
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|  | ee7klt 2005-11-11 04:25:27 | Hi,
I think E123 has got it right and just wanted to add my 2 cents to this to see if this reasoning is right.
I think the quantity of interest is the optical path length (OPL) where since this is really the distance that the light 'sees'?
Thus for first order constructive interefence at the air/oil boundary, we require giving .
|  | E123 2005-11-09 14:52:08 | i think the 200nm instead of 240nm is because of the 1.2 refractive index --> lambda(oil) = lambda(air) / 1.2
yosun 2005-11-09 15:29:14 |
E123: thanks for the better approximation; it has been added.
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f4hy 2009-04-02 17:33:39 |
also it is important to note that the index of refraction of glass is > than that of oil. Otherwise on the reflection there would have been a phase shift of 
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