GR | # Login | Register
  GR0177 #62
GREPhysics.NET Official Solution    Alternate Solutions
This problem is still being typed.
Electromagnetism}Cyclotron Frequency

The cyclotron frequency can be easily derived by equating centripetal force with the Lorentz force. It applies to this problem since the magnetic field is perpendicular to the velocity of the particle. qvB = mv^2/r = mv \omega \Rightarrow \omega = qB/m, where one recalls the angular frequency \omega = v/r.

Solving for m in the cyclotron frequency expression above, one has m=qB/(2\pi f), where one recalls that the angular frequency is related to the frequency by \omega = 2\pi f.

Plug in the numbers to get choice (A).

See below for user comments and alternate solutions! See below for user comments and alternate solutions!
Alternate Solutions
There are no Alternate Solutions for this problem. Be the first to post one!
2019-04-02 05:25:52
I have always thought the \"cyclotron frequency\" referred to the angular frequency, so I left out the 2pi. I feel like ETS should have made which type of frequency they were referring to in the question statement more clearNEC
2007-09-15 11:59:45
I get the correct formula, but I don't know how to plug in the numbers correctly. Can anyone advise?
2007-09-21 20:37:24
The real trick to remember here is that this B-field here is in mks Tesla and happily that is what ETS provides us with; with a Pi in it, to boot! The Pi's will cancel into the angular frquency and the 1600 will cancel out the 1.6 in the electron charge so you'll get something like

m = [2(1.6E-19Coulomb)(Pi/4Tesla)]/[2Pi(1600Hz)] =1/4 E -22 =2.5E-23 kg=> (A)

Drill every day with ETS problems and PERTINENT formulas, get plenty of sleep, eat right, keep a good attitude and good luck!

2017-10-26 19:56:59
lmao dont think thats the kind of advice he wanted, but yeah plant your corn early
Answered Question!

Post A Comment!
Click here to register.
This comment is best classified as a: (mouseover)
Mouseover the respective type above for an explanation of each type.

Bare Basic LaTeX Rosetta Stone

LaTeX syntax supported through dollar sign wrappers $, ex., $\alpha^2_0$ produces .
type this... to get...
$\langle my \rangle$
$\left( abacadabra \right)_{me}$
The Sidebar Chatbox...
Scroll to see it, or resize your browser to ignore it...