GREPhysics.NET: GR0177 #54

GR0177 #54

Problem

GREPhysics.NET Official Solution

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Mechanics $\Rightarrow$ }Impulse

Impulse is defined as $J=\int F dt$ . But, for this problem, one doesn't have to evaluate a messy integral. Instead, the area under the curve is just the sum of two triangles. $J=2\frac{1}{2}(2)(1)=2kgm/s$ , as in choice (C).

Alternate Solutions

ramparts
2009-10-08 10:53:17

Better yet, it's one triangle :P $\frac{1}{2}*2*2 = 2$ kg m/s.

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Comments

fiber 2009-11-05 22:09:52	better yet, put the triangles together and it's one rectange with $A=x\cdot y = 1 \cdot 2$ Reply to this comment
ramparts 2009-10-08 10:53:17	Better yet, it's one triangle :P $\frac{1}{2}22 = 2$ kg m/s. Reply to this comment

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