GR0177 #10



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Comments 
walczyk 20110406 23:16:56  off the subject but how do you find the voltages over the two capacitors?
busy3 20111108 14:14:54 
V1=Q1/C1 , V2=Q2/C2, we know the C's and Q1=Q2 (in series). We can eliminate Q from the equations and get a ratio. We also know V1+V2 =300

  h0dgey84bc 20070921 05:14:03  if C=2E3 F, and V^2=9E4, then surely 0.5*C*V^2 is
=1E3*9E4
=90J
not 0.09J, where does the 1E6 come from in your answer, confused
h0dgey84bc 20070921 05:15:35 
sorry i read micro as milli, my apologies

 

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