GR9677 #89



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Comments 
lukenlow 20180622 12:31:32  I\'m glad that I found this useful information in such a simple explanation, this knowledge will be very useful to me 192.168.l.l   walczyk 20110301 21:50:25  luckily i knew the equation of radius given chord length and chord height (2l and s); everyone's tactics are so much harder, but r = s/2 + l^2/2s, so you're missing a factor of s/2 but since l >> s, its dropped by ETS. then mv^2/r = qvb is all you neat to solve it: p = qbl^2/2s + qbs/2 wooo.
timtamm 20110826 20:16:59 
this solution is rather easy... I am a big big fan... of memorizing and plugging and chugging rather than trying to figure stuff out on a high stress/ timed test. THANKS

nontradish 20120419 20:33:54 
I agree with timtamm to a point. I have been using Dr. Brown's flash cards from Case Western Reserve and have been able to answer many questions off the top of my head. It's better if the physics makes sense too, so you don't have to rely solely memory under pressure;) Good luck to all those taking it on Saturday and in the future!!

  kroner 20091012 07:23:56  An equivalent way to find R is to see that and for some small angle . First order approximations for small are and , so then .
aprilrussell 20180530 03:48:38 
At the very least we can eliminate choice (C) by units. \r\nhttp://fivenightsatfreddys.com

  iostream 20090814 21:32:19  easier way:
if the particle's momentum is very large, then the magnetic field's influence will be negligible  that is, it will move as if it were in a straight line. thus, the momentum should diverge as s approaches 0, from which we eliminate all choices except D and E. then, you realize the binomial approximation is never going to introduce a factor of 8, so the answer is (D).   askewchan 20081106 19:41:29  Also, we can eliminate (A) and (B) because we know that a larger implies greater acceleration which means lower momentum. The same goes for a smaller .
In other words, if the particle has great momentum the radius of this arc will be larger, which gives a greater and lesser .   cordercom 20081005 18:23:40  At the very least we can eliminate choice (C) by units.  

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