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GR9677 #27
Problem
 GREPhysics.NET Official Solution Alternate Solutions
This problem is still being typed.
Lab Methods}Log Graphs

Log graphs are good for exponential-related phenomenon. Thus (A), (C), and (E) are appropriate, thus eliminated. The stopping potential has a linear relation to the frequency, and thus choice (B) is eliminated. The remaining choice is (D).  Alternate Solutions
 Izaac2012-08-21 01:18:44 One can also simply remember that Bode plots (gain VS ) are semilog ones, so obviously D is inappropriate .Reply to this comment Memol
2012-09-18 07:17:56
Can anyone help me with an study reference about these graph stuff? Izaac
2012-08-21 01:18:44
One can also simply remember that Bode plots (gain VS ) are semilog ones, so obviously D is inappropriate . keenanman
2007-10-16 12:38:05
In choice D, the graph gain vs 1/frequency is linear. The graph gain vs frequency is hyperbolic. eshaghoulian
2007-10-02 04:11:09
Just to add a little bit as to why log graphs are good for exponential related phenomena, note that a power law in log-log coordinates is a line:

which is of the form (since is just a constant (like ) and we identify with and with , as these are our new axes in log-log coordinates). So the exponent in the power law becomes the slope in log-log coordinates. Testing this is a GRE favorite, as it is a major tool in experimental physics.
 tachyon7882009-10-06 11:48:47 You have a small math error in your use of logs. The equation should be:      LaTeX syntax supported through dollar sign wrappers $, ex.,$\alpha^2_0$produces . type this... to get...$\int_0^\infty\partial\Rightarrow\ddot{x},\dot{x}\sqrt{z}\langle my \rangle\left( abacadabra \right)_{me}\vec{E}\frac{a}{b}\$