GR9277 #82



Alternate Solutions 
dberger8 20160819 20:19:40  A lot like jmason86, I arrived at the answer a slightly different way. .   jmason86 20090903 19:36:44  I arrived at another way.
By analogy: and in the rotational system you get instead. Since the initial angular velocity was 0, the delta just becomes I = H. Some simple algebra and bam.  

Comments 
dberger8 20160819 20:19:40  A lot like jmason86, I arrived at the answer a slightly different way. .   asa1985 20111006 09:43:46  Torque=dL/dt;
where L is Angular Momentum;
Then H= Troque dt
H= dL
H=L
As we know L= Iw
w=L/I   kroner 20090926 18:13:21  We know will depend on I. The moment of inertia of a linear object like this is going to have a factor of 3 in it somewhere in terms of the mass and length, and there's no way for a factor of 3 to enter into the calculation elsewhere to cancel it out. That leaves choice (D).   jmason86 20090903 19:36:44  I arrived at another way.
By analogy: and in the rotational system you get instead. Since the initial angular velocity was 0, the delta just becomes I = H. Some simple algebra and bam.   Anastomosis 20080409 20:51:25  Although the test book doesn't give the moment of inertia for a plate, it does give it for a rodif you look at it, a plate is just a thick rod, extended in the zdirection (the direction that has no bearing on the moment of inertia).
Anyway, for a rod is , where is just equal to , or in the general case.
So,   FA 20070413 00:29:06  typo alert. there should be no 2 in the denominator of the answer in D)   i3taesun 20070411 01:25:54  Like I=Fdt=delta P, H=torque dt=delta L.
Therefore, we should know the changing quantity of angular momentum.
  cherianjudy 20061103 16:11:02    jcain6 20051123 07:00:05  I think w = at not a/t. This is why w = H/I right?
yosun 20051123 15:02:18 
jcain6: thanks for the typoalert; it has been corrected. (while typing up this solution, my pinky was evidently slashkey happy.)

 

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