GR8677 #17



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casseverhart13 20190930 02:48:03  This is utterly surprising! pressure washing Orlando
danielsw98667 20191021 05:38:21 
With the given stages of radioactivity, the answer is A. LED bike lights

  ernest21 20190810 03:09:30  I would say that muon is a partical from Lepton group so are electron, tauon, neutrino. So the answer must be (A). lol player search   joshuaprice153 20190808 07:20:47  Well, I am so excited that I have found this your post because I have been searching for some information about it almost three hours. You helped me a lot indeed and reading this your article I have found many new and useful information about this subject. air duct   jmason86 20090812 21:37:41  I believe ETS made a typo in the problem statement. The subscript on Y should be Z+1 to be consistent with the rest of the problem.
That is because if Z (the # of protons) decreases by 1, it implies a proton turning into a neutron ( decay). To conserve charge you must emit a positron and to conserve lepton number (from the positron) you must also emit an electron neutrino.
In short, p > n + e
Correct me if I'm wrong :)
segfault 20090822 22:06:46 
After the *first* stage in the process the subscript should be Z+1, but after alpha emission the subscript becomes Z+12=Z1. This is a two step process.

 

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LaTeX syntax supported through dollar sign wrappers $, ex., $\alpha^2_0$ produces .

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$\int_0^\infty$ 

$\partial$ 

$\Rightarrow$ 

$\ddot{x},\dot{x}$ 

$\sqrt{z}$ 

$\langle my \rangle$ 

$\left( abacadabra \right)_{me}$ 

$\vec{E}$ 

$\frac{a}{b}$ 





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